Crossing two heterozygous parents (Aa x Aa) for a trait with simple dominance, what fraction of offspring is expected to show the recessive phenotype?
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Correct answer to question 111 (General Science): One quarter
Method
A Punnett square for Aa x Aa gives genotype ratios of 1 AA : 2 Aa : 1 aa. Only the aa combination shows the recessive trait, which is one out of four offspring.
Updated: November 2026
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